Practical data · A-level Biology

Animal movement and choice-chamber evidence

A distribution tells you where animals were recorded. To explain how it arose, distinguish directional movement from changes in activity and turning.

Specify the question and measurement

State the environmental comparison, the organism and the measured outcome. Counts in chamber areas measure occupancy at defined times. Speed, turning frequency and movement direction require different observations; do not treat an occupancy count as a direct measurement of all three.

Control competing explanations

Make other environmental conditions comparable and consider side preference, light, gradients and chamber geometry. Reversing or randomising which side receives a condition can test position effects. A balanced apparatus supports interpretation but does not guarantee identical behaviour in every animal.

Plan repetitions appropriately

Use a justified number of independent groups or trials. Repeatedly counting the same animals can describe a time course, but the counts are not independent sets of organisms. Handle centre positions consistently and retain the total so that apparent changes are not caused by missing animals.

Separate taxis from kinesis

Movement directed towards or away from a stimulus supports taxis. Changes in speed or turning with stimulus intensity support kinesis. Either can contribute to unequal occupancy; trajectories or activity measurements are needed to discriminate mechanisms rather than naming one from the final distribution alone.

Make a proportionate conclusion

Describe the observed preference or distribution and its variation before proposing a mechanism. Consider acclimatisation and disturbance. Supervised ethical handling and suitable conditions matter; follow the approved practical method and do not expose organisms to extreme conditions to obtain a stronger result.

Worked data example

Of 20 animals, 14 are in the moist region, 4 in the dry region and 2 centrally after the stated interval. Calculate the percentage in the moist region using all animals, then using only those in the two end regions.

Using all animals: 14/20 × 100 = 70%. Using the two end regions: 14/18 × 100 ≈ 77.8%. State the denominator and rule for central animals; the different values do not represent two different observed distributions.

Why are five counts of the same 20 animals not equivalent to five independent groups of 20?

The same individuals contribute repeatedly, so observations can be related through their previous position and behaviour. The counts track that group over time; treating them as independent groups overstates the independent replication.

Practise the related calculations

Averages, spread and mitotic index

Calculate means, medians, ranges and mitotic index. Interpret supplied standard deviations, with sample standard-deviation calculation in OCR mode.

Statistical tests and conclusions

Choose chi-squared, Spearman’s rank or a t-test for suitable data. Interpret supplied critical values, null hypotheses and statistical significance.

Nervous communication and responses: active recall

Original examples and explanations. Check the complete practical requirements in the AQA practical assessment guidance or the OCR A qualification resources.